Designing a Normalized Database from Microsoft
Normalization is the process of redesigning the model to unbundle any overlapping entities. The process involves decomposition; however, decomposition cannot yield a loss of information. You perform the decomposition by applying a linear progression of rules called normal forms. Normalization eliminates redundancy and incompleteness. Note the part that designers frequently overlook: normalization eliminates incompleteness, not just redundancy. Many normal forms (NFs) are defined; the first six are called first NF, second NF, third NF, Boyce-Codd NF, fourth NF, and fifth NF. If a database is in fifth NF, the database is fully normalized. Only the first three NFs are important; usually, if a database is in third NF, it is in fifth NF as well. You should understand the normalization form and use it to perform a final check of your database design, checking the model you created by using other methods.
First Normal Form
Imagine a table such as the one that Table 2-2 shows. The table holds information about sales. In this case, only the OrderId column is part of the primary key.
Table 2-2 Table Before First NF
With a design like this, you can have the following anomalies:
- Insert How do you insert a customer without an order?
- Update If item Bo is renamed, how do you perform an update?
- Delete If order 3 is deleted, the data for customer 2 is lost.
- Select How do you calculate the total quantity of bolts?
Note that only update and select anomalies deal with redundancy: they are problematic because the table contains redundant data. Insert and delete anomalies deal with incompleteness of the model. The rule for first NF is, “A table is in first normal form if all columns are atomic.” This means there can be no multi-valued columns—columns that would hold a collection such as an array or another table. First NF is somewhat redundant with the definition of a relational table or of a relation. A table is a relation if it fulfills the following conditions:
- Values are atomic. The columns in a relational table are not a repeating group or arrays.
- Columns are of the same kind. All values in a column come from the same domain.
- Rows are unique. There is at least one column or set of columns, the values of which uniquely identify each row in the table.
- The order of columns is insignificant. You can share the same table without worrying about table organization.
- The sequence of rows is insignificant. A relational table can be retrieved in a different order and sequence.
- Each column must have a unique name. This is required because the order of columns is not significant.
You can see in the example in Table 2-2 that the last column is multi-valued; it holds an array of items. Before starting with decomposition, let us briefly review the textual notation of a relational table. Remember the earlier example proposition, “Lubor Kollar was employed by Tail-spin Toys on March 19, 2004.” In a general form, you can write “Employee with (Name) was employed by (Company) on (EmploymentDate).” This generalized form of a proposition is a predicate. Terms in parentheses are value placeholders (entity attributes). A predicate defines the structure of a table. You can write the structure briefly as:
Employees(EmpId, EmployeeName, CompanyId, EmploymentDate)
Underlined columns form the primary key. Actually, they form a candidate key, and a table can have multiple candidate keys. You could underline all candidate keys and double underline the primary key.
You decompose the table shown in Table 2-2 on the Items column. Every item leads to a new row, and every atomic piece of data of a single item (ProductId, ProductName, Quantity) leads to a new column. After the decomposition, you have multiple rows for a single order; therefore, you have to expand the primary key. You can compose the new primary key from the OrderId and ProductId columns. However, suppose you can allow multiple products on a single order, each time with a different discount, for example. Thus, you cannot use ProductId as part of the primary key. However, you can add the ItemId attribute and use it as a part of the new primary key. A decomposed table in first normal form would look like this:
Orders(OrderId, CustomerId, OrderDate, ItemId, ProductId, Quantity, ProductName)
Before moving to second NF, you have to understand a common misconception about first NF. You might have heard or read that you should not have a repeating group of columns. However, this advice is incorrect; repeating groups means you should not have a repeating group (that is, a collection) in a single column. For example, imagine this table:
Employees(EmployeeId, EmployeeName, Child1, Child2)
This table is perfectly in first NF. This design has a built-in constraint, allowing only employees who have two children. If you do not allow unknown (NULL) values for the Child1 and Child2 attributes, then you allow employees with exactly two children. This kind of constraint is not typical for business; nevertheless, it is a constraint built into the model, which is in first NF. Such constraints are rare, and a repeating group of columns typically represents a hidden collection. Take care not to decompose such groups automatically before checking whether this is a special constraint.
Second Normal Form
After achieving first NF, the decomposed table from Table 2-2 looks like Table 2-3.
Table 2-3 Table in First NF
You still have the following anomalies:
- Insert How do you insert a customer without an order?
- Update If customer 1 changes the order date for order 1, how do you perform the update? (In many places, possible inconsistencies could exist.)
- Delete If you delete order 3, the data for customer 2 is lost.
To achieve second NF, a table must be in first NF, and every non-key column must be fully functionally dependent on the entire primary key. This means that no column can depend on part of the primary key only. In the example in Table 2-3, you know the customer and the order date if you know the value of the OrderId column; you do not need to know anything about ProductId, which is part of the primary key. The CustomerId and OrderDate columns depend on part of the primary key only—OrderId. To achieve second NF, you need to decompose the table into two tables:
Orders(OrderId, CustomerId, OrderDate) OrderDetails(OrderId, ItemId, ProductId, Quantity, ProductName)
In the Orders table, you leave attributes that depend on OrderId only; then you introduce a new table, OrderDetails, to hold the other attributes. When achieving first NF, you are converting values from a multi-valued attribute to rows and changing the primary key; for second and all other NFs, you decompose tables into more tables. Second NF deals with relationships between columns that are part of a key and other columns.
After decomposing to multiple tables, you must have some common value that enables you to join the tables in queries; otherwise, you would lose some information. The decomposition has to be lossless. Of course, you need relationships between tables. A relationship is an association between two or more tables. Relationships are expressed in the data values of the primary and foreign keys. A primary key is a column or columns in a table whose values uniquely identify each row in the table. A foreign key is a column or columns whose values are the same as the primary key of another table—in other words, a copy of the primary key from another relational table. The relationship is made between two relational tables by matching the values of the foreign key with the values of the primary key.
Third Normal Form
After achieving second NF, the decomposed tables from Table 2-3 look like the tables in Table 2-4 and Table 2-5. Note that in the Orders table (Table 2-4), another attribute, CustomerName, is added to show that normalization violations can appear in any table.
Table 2-4 Orders Table in Second NF
Table 2-5 OrderDetails Table in Second NF
Second NF solves the update anomaly (if customer 1 changes the order date for order 1); however, you still have the following anomalies:
- Insert How do you insert a customer without an order?
- Delete If you delete order 3, the data for customer 2 is lost.
To achieve third NF, a table must be in second NF, and every non-key column must be non-transitively dependent on the primary key. For example, in Table 2-4, from OrderId, you can find CustomerId; then from CustomerId, you can get transitively to the CustomerName attribute value. Similarly, in Table 2-5, you can get transitively to ProductName through Pro-ductId from OrderId and ItemId. If you think of the rule for third NF from the non-key attributes point of view, it simply means you should have no functional dependencies between non-key columns. Non-key columns must depend on keys only. In the examples in Table 2-4 and Table 2-5, CustomerName depends on CustomerId, and ProductName depends on Pro-ductId. Thus, to achieve third NF, you must create new tables for dependencies between non-key columns:
Customers(CustomerId, CustomerName) Orders(OrderId, CustomerId, OrderDate) Products(ProductId, ProductName) OrderDetails(OrderId, ItemId, ProductId, Quantity)
This schema is free from all the update anomalies you had before normalization. However, it is not free from all update anomalies. For example, the schema itself cannot prevent you from inserting an unreasonable order date. (You will learn more about additional constraints in Chapter 3, “Designing a Physical Database.”) Note that this schema is also essentially the same (except for a couple of attributes omitted for the sake of brevity) as you received by using the ORM and ER approach. As mentioned earlier, use normalization for final checking and refining of your model.
Practice: Normalizing the Database
You are developing a database model that will support an application for managing projects (as in the Quick Check in Lesson 1, “Systematically Approaching Design Stages”). You collect the following information: each project has a single customer, each project can have many activities, and each project can have many employees assigned to it. You want to follow time spent (in hours) on projects by specific employee by activity for each day. Your initial design is:
Projects(ProjectId, ProjectName, CustomerId, CustomerName, Activities(Activity1Id, Activity1Name, …, ActivityNId, ActivityNName), Employees(Employee1Id, Employee1Name, …, EmployeeNId, EmployeeNName), WorkDate, TimeSpent)
Exercise 1: Achieve the First Normal Form
In this exercise, you will bring this model to first NF. To achieve first NF, you need to eliminate all attributes that are collections.
- Check the Activities part of the table. Is this a collection?
- Check the Employees part of the table. Is this a collection? Your model should look like this:
Projects(ProjectId, ItemId, ProjectName, CustomerId, CustomerName,
ActivityId, ActivityName, EmployeeId, EmployeeName, WorkDate,
TimeSpent)
Exercise 2: Achieve the Second Normal Form
In this exercise, you will bring this model to second NF. To achieve second NF, you must make sure your model does not contain attributes that depend on only part of the primary key.
- The complete primary key in the table you created in Exercise 1, “Achieve the First Normal Form,” consists of ProjectId and ItemId.
- Do you really need both columns to find CustomerId and CustomerName associated with a project?
Your model should look like this:
Projects(ProjectId, ProjectName, CustomerId, CustomerName)
ProjectDetails(ProjectId, ItemId, ActivityId, ActivityName,
EmployeeId, EmployeeName, WorkDate, TimeSpent)
Exercise 3: Achieve the Third Normal Form
In this exercise, you will bring this model to third NF. To achieve third NF, you need to look at dependencies between non-key attributes.
- Is there any dependency between CustomerId and CustomerName?
- Is there any dependency between ActivityId and ActivityName?
- Is there any dependency between EmployeeId and EmployeeName? Your model should now look like this:
Projects(ProjectId, ProjectName, CustomerId)
ProjectDetails(ProjectId, ItemId, ActivityId, EmployeeId,
WorkDate, TimeSpent)
Customers(CustomerId, CustomerName)
Activities(ActivityId, ActivityName)
Employees(EmployeeId, EmployeeName)
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